0.15X^2-0.1x=2

Solution for 0.15X^2-0.1x=2 equation:

0.15X^2-0.1X=2

We move all terms to the left:

0.15X^2-0.1X-(2)=0

a = 0.15; b = -0.1; c = -2;
Δ = b2-4ac
Δ = -0.12-4·0.15·(-2)
Δ = 1.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.1)-\sqrt{1.21}}{2*0.15}=\frac{0.1-\sqrt{1.21}}{0.3}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.1)+\sqrt{1.21}}{2*0.15}=\frac{0.1+\sqrt{1.21}}{0.3}
$